H(x)=2x^2+4x+16

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Solution for H(x)=2x^2+4x+16 equation: 



(H)=2H^2+4H+16

We move all terms to the left:

(H)-(2H^2+4H+16)=0

We get rid of parentheses

-2H^2+H-4H-16=0

We add all the numbers together, and all the variables

-2H^2-3H-16=0

a = -2; b = -3; c = -16;
Δ = b2-4ac
Δ = -32-4·(-2)·(-16)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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